Kinematics
Kinematics
Kinematics
what you'll learn
Lesson details
Units 1 & 2 (Kinematics and Motion Modelling)
Introduce kinematics in a calculus context by modelling linear motion using displacement, velocity, and acceleration functions. Explore how differentiation and integration describe motion, interpret motion graphs, and solve problems involving time, distance, and change in velocity.
Unit 2: Calculus in Motion (Kinematics)
2.1 Modelling Motion with Functions
Displacement Function: s(t), position of an object over time
Velocity: first derivative of displacement, v(t) = s′(t)
Acceleration: second derivative, a(t) = v′(t) = s″(t)
Units: e.g. m, m/s, m/s² (depending on context)
2.2 Interpreting Motion Graphs
Displacement-Time Graphs: shape and slope indicate velocity
Velocity-Time Graphs: slope gives acceleration; area under curve gives displacement
Acceleration-Time Graphs: area gives change in velocity
Turning Points: when velocity = 0 (object at rest or changing direction)
2.3 Solving Motion Problems
Given s(t): find v(t), a(t) using differentiation
Given a(t) or v(t): find v(t), s(t) using integration (+ initial conditions)
Total Displacement: ∫ₐᵇ v(t) dt
Total Distance: integrate |v(t)| over given time intervals
2.4 Real-World Applications
Vertical motion under gravity: s(t) = –½gt² + v₀t + s₀
Projectile motion in one dimension
Determining maximum height, time of flight, and impact velocity
Use of initial conditions to solve for constants in integration
2.5 Technology and Graphical Analysis
CAS for solving and checking derivative/integral expressions
Graphing motion functions to visualise movement over time
Interpreting motion behaviour through graphical intersections and extrema
Units 1 & 2 (Kinematics and Motion Modelling)
Introduce kinematics in a calculus context by modelling linear motion using displacement, velocity, and acceleration functions. Explore how differentiation and integration describe motion, interpret motion graphs, and solve problems involving time, distance, and change in velocity.
Unit 2: Calculus in Motion (Kinematics)
2.1 Modelling Motion with Functions
Displacement Function: s(t), position of an object over time
Velocity: first derivative of displacement, v(t) = s′(t)
Acceleration: second derivative, a(t) = v′(t) = s″(t)
Units: e.g. m, m/s, m/s² (depending on context)
2.2 Interpreting Motion Graphs
Displacement-Time Graphs: shape and slope indicate velocity
Velocity-Time Graphs: slope gives acceleration; area under curve gives displacement
Acceleration-Time Graphs: area gives change in velocity
Turning Points: when velocity = 0 (object at rest or changing direction)
2.3 Solving Motion Problems
Given s(t): find v(t), a(t) using differentiation
Given a(t) or v(t): find v(t), s(t) using integration (+ initial conditions)
Total Displacement: ∫ₐᵇ v(t) dt
Total Distance: integrate |v(t)| over given time intervals
2.4 Real-World Applications
Vertical motion under gravity: s(t) = –½gt² + v₀t + s₀
Projectile motion in one dimension
Determining maximum height, time of flight, and impact velocity
Use of initial conditions to solve for constants in integration
2.5 Technology and Graphical Analysis
CAS for solving and checking derivative/integral expressions
Graphing motion functions to visualise movement over time
Interpreting motion behaviour through graphical intersections and extrema
Units 1 & 2 (Kinematics and Motion Modelling)
Introduce kinematics in a calculus context by modelling linear motion using displacement, velocity, and acceleration functions. Explore how differentiation and integration describe motion, interpret motion graphs, and solve problems involving time, distance, and change in velocity.
Unit 2: Calculus in Motion (Kinematics)
2.1 Modelling Motion with Functions
Displacement Function: s(t), position of an object over time
Velocity: first derivative of displacement, v(t) = s′(t)
Acceleration: second derivative, a(t) = v′(t) = s″(t)
Units: e.g. m, m/s, m/s² (depending on context)
2.2 Interpreting Motion Graphs
Displacement-Time Graphs: shape and slope indicate velocity
Velocity-Time Graphs: slope gives acceleration; area under curve gives displacement
Acceleration-Time Graphs: area gives change in velocity
Turning Points: when velocity = 0 (object at rest or changing direction)
2.3 Solving Motion Problems
Given s(t): find v(t), a(t) using differentiation
Given a(t) or v(t): find v(t), s(t) using integration (+ initial conditions)
Total Displacement: ∫ₐᵇ v(t) dt
Total Distance: integrate |v(t)| over given time intervals
2.4 Real-World Applications
Vertical motion under gravity: s(t) = –½gt² + v₀t + s₀
Projectile motion in one dimension
Determining maximum height, time of flight, and impact velocity
Use of initial conditions to solve for constants in integration
2.5 Technology and Graphical Analysis
CAS for solving and checking derivative/integral expressions
Graphing motion functions to visualise movement over time
Interpreting motion behaviour through graphical intersections and extrema
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